Answer:
P/Q = (-3x +2)/(3(3x -1))
PQ = 12/((3x -1)(-3x +2))
Step-by-step explanation:
You want the quotient and product of P(x) = 2/(3x -1) and Q(x) = 6/(-3x +2).
Quotient
The quotient is found by multiplying by the inverse of the denominator:
[tex]P(x)\div Q(x)=\left(\dfrac{2}{3x-1}\right)\div\left(\dfrac{6}{-3x+2}\right)=\left(\dfrac{2}{3x-1}\right)\times\left(\dfrac{-3x+2}{6}\right)\\\\\\\dfrac{2(-3x+2)}{6(3x-1)}=\boxed{\dfrac{-3x+2}{3(3x-1)}}[/tex]
Product
As with multiplying any fractions, the numerator is the product of the numerators, and the denominator is the product of the denominators.
[tex]P(x)\times Q(x)=\left(\dfrac{2}{3x-1}\right)\times\left(\dfrac{6}{-3x+2}\right)=\dfrac{2\cdot 6}{(3x-1)(-3+2)}\\\\\\=\boxed{\dfrac{12}{(3x-1)(-3x+2)}}[/tex]
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Additional comment
Usually the simplified form would contain no parentheses. The indicated products would be multiplied out.
