If Tamika adds two separate numbers at random from the collection, the likelihood that her result will be higher than Carlos' result is 4/9. To multiply two random integers from the set, Carlos chooses two more random numbers.
This event has a chance of happening or not happening.
calculation
Tamika might receive any of the following results, all of which are equally likely:
8+9=17
8+10=18
9+10=19
The various potential values that Carlos could receive—all equally likely—are:
3 * 5=15
3 * 6=18
5 * 6=30
Because 17 is only greater than 15, the likelihood that Tamika's total would be greater than Carlos's set is 1/3.
Because 18 is only greater than 15, the likelihood that Tamika's total would be greater than Carlos's set is 1/3.
Due to the fact that 19 is greater than both 15 and 18, the likelihood that Tamika's total would be greater than Carlos's set is 2/3.
We have 1/3(1/3+1/3+2/3)=1/3(4/3)=4/9 since each sum has a 1/3 chance of being chosen.
the likelihood of the difference between Tamika's performance and Carlos' performance is 4/9.
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