what is the angular momentum of a 2.8- kg uniform cylindrical grinding wheel of radius 26 cm when rotating at 1500 rpm ?

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21-12-2022
Physics

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what is the angular momentum of a 2.8- kg uniform cylindrical grinding wheel of radius 26 cm when rotating at 1500 rpm ?

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tutorconsortium632 tutorconsortium632 · Answer 1 · 2022-12-28T09:05:38-05:00

1500 rpm * 2pi rad is equal to 9424.78 rad/m (9424.78 rad/m) /60 s is equal to 157.08 rad/s. I = 1/2mr2 I = 1/2(2.8 kg)(.18 m) (.18 m) 2 = 0.04536 kgm2 L = Iw = 7.13 kgm2/s = (0.04536 kgm2)(157.08 rad/s).

What is a 0.270-kilogram ball's angular momentum when it is rotating?

For a point mass traveling in a circle with radius r, the moment of inertia will be equal to Mr squared. Angular momentum is defined as the moment of inertia times angular velocity. Therefore, the angular momentum is equal to 5.12-kilogram meters squared per second (0.270 kilograms times 1.35 meters squared times 10.4 radians per second).

How do you calculate the RPM of cylindrical grinding?

The formula is new rpm = original rpm (original diameter current diameter)1.5 if you want to keep the chip load precisely the same. So, once it drops to 15", run your new 18" wheel at 2,366 rpm [1,800 (18 15)1.5] if you were operating it at 1,800 rpm—again, within tolerance.

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