Answer :
Cobalt-56 has a decay constant of 8.77 × 10-3 (which is equivalent to a half-life of 79 days). the cobalt-56 decay time is 141 days. Option E
What is Cobalt-56?
Generally, To solve this problem, you can use the formula for exponential decay:
N(t) = N0 * e^(-kt)
where N(t) is the quantity of the substance at time t, N0 is the initial quantity of the substance, k is the decay constant, and t is the time.
We are given that the decay constant for cobalt-56 is k = 8.77 × 10^-3, and we want to find the time t it takes for the sample to decay to 62% of its original value. We can rearrange the formula to solve for t:
t = (1/k) * ln(N0/N(t))
Plugging in the values, we get:
t = (1/(8.77 × 10^-3)) * ln(1/0.62)
= 113.6 days
Therefore, the correct answer is (e) 141 days.
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