to pass a slow-moving truck, you need your 1300 kg car to accelerate from 13.4 m/s to 17.9 m/s in 3 seconds. what is the power required to pass



Answer :

Answer:

P = E / t      definition of power

P = (1/2 m v2^2 - 1/2 m v1^2) / t

P = m / (2 * t) * (v2^2 - v1^2)

P = 1300 kg / 6 sec * (17.9^2 - 13.4^2)

P = 217 * 141 = 30,600 J/sec