Dwight sits near a bowl of candies in his office. he observed how many candies each person took in a sample of 444 visits. here is how many candies each person took: 1, 2, 1, 41,2,1,41, comma, 2, comma, 1, comma, 4 dwight found the mean was \bar x=2 x ˉ =2x, with, \bar, on top, equals, 2 candies. he thinks the standard deviation is s_x =\sqrt{\dfrac{(1-2)^2 (2-2)^2 (1-2)^2 (4-2)^2}{3}}s x = 3 (1−2) 2 (2−2) 2 (1−2) 2 (4−2) 2 s, start subscript, x, end subscript, equals, square root of, start fraction, left parenthesis, 1, minus, 2, right parenthesis, squared, plus, left parenthesis, 2, minus, 2, right parenthesis, squared, plus, left parenthesis, 1, minus, 2, right parenthesis, squared, plus, left parenthesis, 4, minus, 2, right parenthesis, squared, divided by, 3, end fraction, end square root what is the error in dwight's standard deviation calculation?

Standard deviation is a measure of the amount of variation or spread in a set of values. A low standard deviation indicates that the values tend to be closer to the mean (also called mean) of the set, while a high standard deviation indicates that the values are more spread out.

According to the Question:

Given that mean {x} = 2

x = 2.

[tex]x_i[/tex] from i = 1 to 4 is x₁ = 1 , x₂ = 2, x₃ = 1 and x₄ = 4.

Since each deviation is the difference between each data point (1, 2, 1, 4) and 2

So ,[tex](x_i - X)^2 = (1 - 1)^2 + (2 - 2)^2 + (1 - 2)^2 + (4 - 2)^2[/tex]

This is divided by N -1 = 4 - 1 = 3

Therefore,

There is no error in Dwight's standard deviation formula.

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