The angle of the ramp in relation to the horizontal component of the box is 1.42°
The mass of the block is 0.35 kg
The rate at which the box accelerates = 1.5 m/s²
The angle of the ramp can be found using the formula,
F = mgcosθ
where F is the force
m is the mass
g is the acceleration due to gravity
θ is the angle of the ramp
We also know that
F = ma
Thus,
ma = mgcosθ
a = gsinθ
Let us rearrange the above equation,
θ = cos⁻¹(a/g)
Let us substitute the known values in the above equation, we get
θ = cos⁻¹ (1.5 / 9.8)
= cos⁻¹ (0.15)
= 1.42°
Therefore, the angle of the ramp is 1.42°
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