The margin of error for the estimate of the mean number of television hours watched is 1.13
In this question we have been given the dotplot below shows the distribution of the sample mean hours of TV watched for 500 random samples of size 25 taken with replacement from the original sample.
We need to use results of the simulation to approximate the margin of error for the estimate of the mean number of hours of television watched.
Sample size, n = 25
Standard deviation = 2.88
Confidence level = 95%
So, the probability is p = 0.95
The z' = 1.96
The approximate margin of error can be calculated using the formula:
margin of error = z' * √(σ²/n)
margin of error = 1.96 * √(2.88²/25)
margin of error = 1.13
Therefore, the margin of error = 1.13
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