Answer :
It takes 10 sec for the car to stop as it decreases its velocity from 30 m/s to 0 m/s.
Given that,
Force on the car = 3000 N
Mass of the car = 1000 kg
As it is said that, the car reduces its velocity from 30 m/s to 0 m/s, the car is said to be decelerating.
From Newton's second law, we know that, F = m* a
where, m is the mass
a is the acceleration
Making 'a' as subject, we have,
a = F/m = 3000/1000 = 3 m/s² (deceleration)
Deceleration = (Initial velocity - Final velocity)/time
Making time as subject, we have,
Time = (Initial velocity - Final velocity)/ Deceleration = (30 - 0)/3 = 10 sec
So, the car is said to stop in 10 sec.
The question is incomplete. The complete question is ' The brakes of a 1000kg car exert 3000N. How long will it take the car to come to a stop from a velocity of 30meter per second and how far will the car travel during this time?'
To know more about time:
https://brainly.com/question/26877615
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