Answered

a 2.25 h inductor carries a steady current of 0.485 a. when the switch in the circuit is thrown open, the current is effectively zero in 10.0 ms. what is the average induced emf in the inductor during this time?



Answer :

The required average induced EMF in the inductor when the switch is open in the circuit is 109.195 volt.

Given that,

The value of inductance L = 2.25 H

The current flow is equal to 0.485 A

When switch is open, current becomes 0 in 10 ms

So, the change in current

di = 0.485 - 0 = 0.485 A

Time taken to change the current

dt = 10 ms = 0.01 sec

We know the expression for induced EMF as e = L (di/dt)

Substituting the values in the above equation, we have,

So, e = L (di/dt) = 2.25* (0.485/0.01) = 109.195 volt

Thus, the required induced EMF will be 109.195 volt.

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