Answer :
The constants that have to multiply to eliminate one variable from the system are 12 and 5.
The equations are
5x+13y = 232
12x + 7y = 218
Elimination Method
The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with multiplication or division of coefficients of the variables
Both x term and y terms, choose x terms and apply the elimination method
The coefficient of x in the first equation is 5 and 12 in the second equation
Coefficient is a number that is being multiplied by the variable. 2x+6x+14. The 2x, 6x, and 14 are terms because they are being added together. 2 and x; 6 and x are factors because they are being multiplied together. 2 from 2x and 6 from 6x are the coefficients because they are being multiplied by the variable.
To make it the same
Prime factorization
Prime factorization is a process of writing all numbers as a product of primes.
5 = 5×1
12 = 2×2×3
LCM (5, 12 ) = 2×2×3×5 = 60
Multiply the first equation by 12 and the second equation by 5
60x + 156y = 2784
60x + 35y = 1090
Subtract equation 2 from equation 1
121y = 1694
Eliminated x term
The constants that we have to multiply to eliminate one variable from the system are 12 and 5
The complete question is:
Which constants can be multiplied by the equations so one variable will be eliminated when the systems are added together? 5x + 13y = 232
12x + 7y = 218
To learn more about Elimination Method visit:
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