Answer :

1/S' + 1/S = 1/f

-1/4 +1/S = 1/5

S = 20/9 mm  = 2.22 mm

1/v-1/u=1/f

So

1/(-4)-1/u=1/5

So

v=-2.22mm in front of lens as we are getting same sign as that for image i.e negative

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The object of this image will be formed in front of lens with object distance v of -2.22 mm.

1/S' + 1/S = 1/f

-1/4 +1/S = 1/5

S = 20/9 mm  = 2.22 mm

1/v-1/u=1/f

So

1/(-4)-1/u=1/5

So

v=-2.22mm in front of lens as we are getting same sign as that for image i.e negative.

  • Concave lenses or diverging lenses divert light rays, whilst convex lenses or converging lenses focus light rays to a particular spot. In accordance with the laws of refraction, a lens is a transparent substance with a flat or curved surface.
  • Positive, or converging, narrow lenses combine incident light rays that are parallel to the optical axis and focus them at the focal plane to create a true image.

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