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McKenna wa aked to write the following expreion in tandard form. When writing the expreion in tandard form, McKenna made a mitake. A. McKenna made her firt mitake in. B. The correct expreion in tandard form i. 3 − 5(3a 6)
3 − 5(3a 6)
3 (−5)(3a 6)
−2(3a 6)
−6a (−12)
−6a − 12
Step 1
Step 2
Step 3
Step 4



Answer :

A. McKenna made a mistake in Step 2.

B. The correct expression in standard form is -15a-27.

A linear equation in one variable is an equation which has a maximum of one variable of order 1.

The standard form of linear equations in one variable is represented as:

ax + b = 0

Where,

  • ‘a’ and ‘b’ are real numbers.
  • Both ‘a’ and ‘b’ are not equal to zero.

You would need to multiply -5 by 3a and 6, not add 3 to it first.

The correct steps would be:  

3−5(3a+6)

3+(−5)(3a+6) : Step 1

3 - 15a - 30   :Step 2

-15a - 27        :Step 3

Thus ,the correct expression formed in standard form is -15a-27a.

A. McKenna made a mistake in Step 2.

B. The correct expression in standard form is -15a-27.

To know more about standard form refer to:

brainly.com/question/29000730

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