7. imagine a long board (100 m). a 1 kg block sits 75 m from the left. if the board is 4 kg, where should the pivot point be placed to balance?

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20-12-2022
Physics

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7. imagine a long board (100 m). a 1 kg block sits 75 m from the left. if the board is 4 kg, where should the pivot point be placed to balance?

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NehaKumari123 NehaKumari123 · Answer 1 · 2022-12-23T09:28:01-05:00

A) The pivot should be positioned at a distance of x = 2.25 m from the adult in order to balance the board while disregarding the bulk of the board.

B) If the board is uniform and weighs 15 kg, the pivot point is x = 2.54 m away from the adult.

We are given;

Mass of adult; M1 = 75 kg

Length of board = 9 m

Mass of child; M2 = 25kg

A) If the mass of the board is ignored, then the pivot point from the adult should be at x.

Consequently, pause to consider the pivot;

75x = 25(9 - x)

75x = 225 - 25x

75x + 25x = 225

100x = 225

x = 225/100

x = 2.25 m

B) The board is described as being uniform and weighing 15 kg.

The focus of action will be this pile of board.

Board center is 9/2 = 4.5 meters.

Now, consider the previous pivot for a second;

75x = 15(4.5 - x) + 25(9 - x)

75x = 67.5 - 15x + 225 - 25x

75x = 67.5 + 225 - 40x

115x = 292.5

x = 292.5/115

x = 2.54 m

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