The total energy of the system is 2.025 J
By conservation of energy, Initial energy= final energy, thus speed of the block will be 3m/s.
Mass of block = 0.25 kg
Spring constant = 180N/m
Block is displaced by 15cm = 0.15m
Total energy of the system = 1/2 kx²
=1/2 × 180× (0.15)²
=2.025 J
When block is 10cm from its equilibrium position
Initially at t=0, spring energy = 2.025 J
Kinetic energy = 0 (Block is in rest)
Finally,
spring energy = 1/2 kx²=1/2 ×180×(0.10)²
And kinetic energy = 1/2 mv²=1/2 ×0.25×v²
Now by conservation of energy
Initial energy= Final energy
2.025= 0.9 + 0.25/2 ×v²
1.125=0.25/2 × v²
v²= 1.125×2/0.25= 9
Therefore, v=3
Speed of block = 3m/s
To know more about conservation of energy, click on https://brainly.com/question/166559
#SPJ4