a city's population is declining continuously at a rate of 6.1% each year. if the population of the city is currently 435,410, what will the population of the city be in 8 years? (2 points) 222,930 263,162 266,945 267,278



Answer :

the population of the city be in 8 years is  263,162 if if the population of the city is currently 435,410

The rate at which the population is decreasing is exponential. We would apply the exponential decay formula which is expressed as

A = P(1 - r)^t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of decrease.

From the information given,

P = 435410

r = 6.1% = 6.1/100 = 0.061,

t = 8 years

Therefore,

A = 435410(1 - 0.061)^8

A = 435410(0.939)^8

A = 263162

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