Answer :
The iterated triple integrals for the volume of the tetrahedron cut from the first octant by the plane XYZ is 84
The term iterated triple integrals means the result of applying integrals to a function of more than one variable (for example or ) in a way that each of the integrals considers some of the variables as given constants.
Here we have to write six different iterated triple integrals for the volume of the tetrahedron cut from the first octant by the plane XYZ and then we have to evaluate the first integral.
Here in this case we will integrate with respect to y first.
Therefore, the iterated integral that we need to compute is,
∬6xy²dA=∫⁴₂∫₁²6xy²dydx
When we per the first stage integral, then we get,
=> ∫⁴₂ (2xy³)₁²dydx
When we expand it then we get,
=> ∫⁴₂ [16x - 2x] dx
=> ∫⁴₂ 14x dx
Then we further integrate this one, then we get.,
=> ∫⁴₂ 14x dx = [7x²]₂⁴
=> [7(4)² - 7(2)²]
=> 112 - 28
=> 84
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