a vertical cylindrical tank with diameter 2 m and height 5 meter is full of water. how much work is required to pump all the water to the top of the tank? use 1000 kg / m3 for the density of water and 9.8 m /s2 for the acceleration due to gravity. (volume of a cylinder: 2 v r h



Answer :

The work required to pump all the water to the top of the tank is 769300Js when a vertical cylindrical tank with diameter 2 m and height 5 meter is full of water.

Given diameter of cylindrical tank (d) = 2m

radius of cylinder (r) = 1m

Height of water tank (h) = 5m

density of water = 1000kg/m^3

acceleration due to gravity (g) = 9.8m/s^2

Volume of cylinder (V) = πr^2h = 3.14x1x1x5 = 15.7m^3

Work done (W) = F.dx

dW = dF .dx

dW = dmgdx (As F = mg)

we know that mass = density x volume

W = density x (V) x g x h = 1000x15.7x9.8x5 = 769300Js

Hence work required to pump all the water to the top of the tank is 769300Js

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