write the equations used to convert from spherical to rectangular coordinates, and then calculate (showing your work!) the jacobian of this transformation.



Answer :

Equation representing the conversion of spherical coordinates to rectangular coordinates are r = √ x² + y² + z² , φ = cos⁻¹( z/r) ,

θ = tan⁻¹(y/x) and Jacobian transformation is given by :

[tex]d(x, y, z)/ d(r, \theta, \phi ) =\left|\begin{array}{ccc}dx/dr&dx/d\theta&dx/d\phi\\dy/dr&dy/d\theta&dy/d\phi\\dz/dr&dz/d\theta&dz/d\phi\end{array}\right|[/tex]

As given in the question,

In the spherical coordinates are ( r, θ, φ ) to the given rectangular coordinates in the cartesian plane  are ( x, y , z)

Equation representing the conversion of  spherical and rectangular coordinates is given by:

x = rcosθsinφ

y = rsinθsinφ

z = rcosφ

Where

0 ≤ r <∞ ,  0≤ θ< 2π , 0≤φ<  π

r = √ x² + y² + z²

φ = cos⁻¹( z/r)

θ = tan⁻¹(y/x)

Jacobian transformation is given by:

[tex]d(x, y, z)/ d(r, \theta, \phi ) =\left|\begin{array}{ccc}dx/dr&dx/d\theta&dx/d\phi\\dy/dr&dy/d\theta&dy/d\phi\\dz/dr&dz/d\theta&dz/d\phi\end{array}\right|[/tex]

Where,

dx/dr = cosθsinφ

dx/dθ = -rsinθsinφ

dx/dφ = rcosθcosφ

dy/dr = sinθsinφ

dy/dθ = rcosθsinφ

dy/dφ = rsinθcosφ

dz/dr = cosφ

dz/dθ = 0

dz/dφ = -rsinφ

Therefore, the conversion of spherical coordinates to rectangular coordinates are given by : r = √ x² + y² + z² , φ = cos⁻¹( z/r) ,θ = tan⁻¹(y/x) and Jacobian transformation is given by :

[tex]d(x, y, z)/ d(r, \theta, \phi ) =\left|\begin{array}{ccc}dx/dr&dx/d\theta&dx/d\phi\\dy/dr&dy/d\theta&dy/d\phi\\dz/dr&dz/d\theta&dz/d\phi\end{array}\right|[/tex]

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