Gordon and tess are trying to determine whether δabc and δfge can be proven congruent through rigid motions. gordon says that δabc ≅ δfge because δabc can be reflected over the line x = 1 to create δfge. tess says δabc ≅ δfge because δabc can be translated by the rule (x 5, y − 7) to create δfge. a coordinate grid with triangles abc and efg at a negative 7 comma 2, b negative 3 comma 6, c negative 2 comma 1, e 2 comma negative 1, f 7 comma negative 2, and g 3 comma negative 6 who is correct? gordon only tess only both gordon and tess neither gordon nor tess



Answer :

The correct answer is Neither Gordon nor Tess .

Given :

The vertices ABC are in clockwise order. The corresponding vertices FGE are also in clockwise order. On this basis, you can say that there cannot be a single reflection ( as across x = 1 ), because that would reverse the order to counter clockwise. Gordon cannot be correct.

The left-right orientation of vertices A and C is reversed to a right-left orientation for corresponding vertices F and E. This means two reflections or a rotation is involved. Translation cannot reverse the orientation like this, so Tess cannot be correct.

ΔFGE and ΔABC are a reflection of each other across the origin, equivalent to the two reflections "across the x-axis" and "across the y-axis." This is also equivalent to a rotation of 180° about the origin.

Neither Gordon nor Tess is correct.

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