Answer:
(C) 2015
Step-by-step explanation:
Assuming that A = 600e^34
To find out when the account will be worth $10,000, we need to solve the equation A = 10,000 for t, where t is the number of years after 2010. We can do this by rearranging the equation to solve for t:
A = 10,000
600e^(34t) = 10,000
(34t) = ln(10,000/600)
t = ln(10,000/600) / 34
Now we need to find out what year this corresponds to. Since t represents the number of years after 2010, we can add 2010 to t to find the year in which the account will be worth $10,000.
Year = 2010 + t = 2010 + ln(10,000/600) / 34 = 2015.
So the account will be worth $10,000 in the year 2015. Therefore, the correct answer is (C) 2015.