a spring has a natural length of 10 m. if the work done in stretching the spring from 10 m (its natural length) to 11 m is 5 2 joules, what is the force in newtons needed to stretch the spring from its natural length to a length of 20 m?

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19-12-2022
Physics

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a spring has a natural length of 10 m. if the work done in stretching the spring from 10 m (its natural length) to 11 m is 5 2 joules, what is the force in newtons needed to stretch the spring from its natural length to a length of 20 m?

Answer :

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kjuli1766 kjuli1766 · Answer 1 · 2022-12-21T14:09:47-05:00

The force in newtons needed to stretch the spring from its natural length to a length of 20 m is 104 N

As the metal spring expands and contracts, it deviates from its equilibrium position. The result is a restoring force that tends to push the spring back to its original position. This force is called spring force.

Given;

Natural length=10m

Work done to stretch from 10m to 11m =5.2J

so change in length (x)=1m

Work done on spring(W) = 1/2 *k *x^2

5.2 =1/2*k*1^2

so, k=10.4N/m

Spring is stretch to 20m so new x=10m

Force needed to stretch the spring = kx = 10.4 *10= 104 N

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