Answer :

Medunno13

Answer:

[tex]k<1, k>5[/tex]

Step-by-step explanation:

[tex]3x+1=x^2+kx+2 \\ \\ x^2+x(k-3)+1=0 \\ \\ \Delta>0 \implies (k-3)^2-4(1)(1)>0 \\ \\ (k-3)^2-2^2>0 \\ \\ (k-1)(k-5)>0 \\ \\ k<1, k>5[/tex]

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