if a fair coin is tossed 100 times. the distribution of the number of heads is b(100, 0.5). what is the probability that the obtained heads, x, is between 45 and 55? p (45 less or equal than x less or equal than 55 )



Answer :

The probability that obtained heads, x, is between 45 and 55 is 0.6826.

The Binomial distribution provides the precise response. Wolfram Alpha is one of the software tools that may perform the computation for you. Using this method manually is painful.

Maybe you're supposed to use the binomial's normal approximation. If there are X heads, then X has a roughly normal distribution first we have to find what is the mean and standard deviation.

Given that n = 100 is a relatively large number, we will assume a normal distribution.

mean M = n*p 100*0.5 =50

Consequently, Sd = √(npq) = √1000.5*0.5 = 5.

The standard deviation is 5.

Z = x-µ/σ

Z = (x-50)/5

we have to find the probability in this range.

P(45<X<55) = P((45-50)/5<X<(55-50)/5

P(-1<X<1) = 0.8413  - 0.1587

0.6826

To know more about probability here:

https://brainly.com/question/30034780

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