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a 60-hz induction motor is needed to drive a load at approximately 895rpm. part a determine the maximum number of poles required to drive the load at 895 rpm . express your answer as an integer. p



Answer :

varshamittal029

The maximum number of poles required to drive the load is 8.

full load speed = 120*f/p

850 = 120*60/p

p = 120*60/850

p = 8.47

since no. of poles are even so

p = 8

if number pole p = 8

synchronous speed Ns = 120*f/p = 120*60/8 = 900RPM

SLIP = (Ns - N)/Ns

s = (900-850)/900

s = 0.056

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