Answer :
i) The statement P(A Ո B) = P(A) Ո P(B) is false.
ii) The statement P(A Ս B) = P(A) U P(B) is false.
iii) The statement P(A) U P(B) ⊆ P(A U B) is true.
Sets are groups of well-defined objects or components in mathematics. A set is denoted by a capital letter, and the cardinal number of a set is enclosed in a curly bracket to indicate how many members there are in a finite set. For example, set A is a collection of all the natural numbers, such as A = {1,2,3,4,5,6,7,8,…..∞}.
i) Let A ={0,1} and B ={1,2}
Thus, A Ո B = {1}
P(A Ո B) = {∅, {0}, {1}, {2}, {0,1} , {1,2}, {0,2}}
P(A) = {∅, {0}, {1}, {0,1}}
P(B) = {∅, {1}, {2},{1,2}}
P(A) Ո P(B) = {∅, {1}}
∴ P(A Ո B) ≠ P(A) Ո P(B)
So, the given statement is false.
ii) Let A ={0,1} and B ={1,2}
Thus, A Ս B = {0,1,2}
P(A Ս B) = {∅, {0}, {1}, {2}, {0,1} , {1,2}, {0,2}, {0,1,2}}
P(A) = {∅, {0}, {1}, {0,1}}
P(B) = {∅, {1}, {2},{1,2}}
P(A) U P(B) = {∅, {0}, {1}, {2}, {0,1} , {1,2}}
∴ P(A Ս B) ≠ P(A) U P(B)
So, the given statement is false.
iii)
If X⊆Y then P(X)⊆P(Y) (1)
If X⊆Z and Y⊆Z then X∪Y⊆Z. (2)
Necessarily A⊆A∪B,
P(A)⊆P(A∪B); (a)
similarly, B⊆A∪B,
P(B)⊆P(A∪B). (b)
From (a) and (b), using (2), we conclude:
P(A) ∪ P(B) ⊆ P(A ∪ B).
So, the given statement is true.
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