imagine the speed of light in antoher universe to be only 200m/s. two cars are teaveling along a high3ay in opposite directions. car 1 is traveling 50m/s, and car 2 is traveling 70m/s. how fast does person ridingin cqr 1 measure person riding in car 2 to be traveling?



Answer :

The person riding in car 1 would measure the person riding in car 2 to be traveling at a speed of 63.91m/s.

If the speed of light in another universe is 200m/s and two cars are traveling in opposite directions along a highway, the speed at which a person riding in car 1 measures the person riding in car 2 to be traveling can be calculated using the following formula:

v' = (v + v0)/(1 + vv0/c²)

where v' is the measured speed, v is the actual speed of the object, v0 is the speed of the observer, and c is the speed of light in the given universe.

In this case, the actual speed of car 2 is 70m/s and the speed of car 1 is 50m/s. Plugging these values into the formula, we get:

v' = (70 + 50)/(1 + 70 × 50/200²) = 120/(1 + 3500/40000) = 120/1.875 = 63.91m/s.

Learn more about relative velocity at

https://brainly.com/question/29398891?referrer=searchResults

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