Answer :
The net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field is 1.039 * 10⁻⁴ N m.
The torque is described as
τ = N* I* B* A* sin θ
Where,
N = Number of loops
I = Current
B = Magnetic Field
A = Cross-sectional Area
θ = Angle between the loop and the magnetic field.
At this case the angle would be θ = 90° - 30° = 60°
Given that,
I = 0.5 A
B = 0.3 T
A = (0.04) (0.02) = 8* 10⁻⁴ m
N = 1
Replacing in our equation we have
τ = N* I* B* A* sin θ
τ = 1* 0.5* 0.3* 8* 10⁻⁴* sin 60°
τ = 1.039 * 10⁻⁴ N m
Therefore, the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field is 1.039 * 10⁻⁴ N m.
The question is incomplete. The complete question is 'Assume that the loop is initially positioned at θ = 30° and the current flowing into the loop is 0.500 A . If the magnitude of the magnetic field is 0.300 T , what is τ,'
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