a bag contains different colored beads. the probability of drawing two black beads from the bag without replacement is 335, and the probability of drawing one black bead is 310. what is the probability of drawing a second black bead, given that the first bead is black?



Answer :

The probability of drawing a second black bead, given that the first bead is black, is 1/3 or 0.33.

The probability of drawing two black beads from a bag without replacement is given as 335. The probability of drawing one black bead is also given as 310. To calculate the probability of drawing a second black bead, given that the first bead is black, we can use the formula P(B2|B1) = P(B1 and B2) / P(B1). The probability of drawing one black bead is P(B1) = 310. The probability of drawing the two black beads is P(B1 and B2) = 335. Therefore, P(B2|B1) = 335 / 310 = 1/3 = 0.33.

The probability of drawing two black beads from a bag without replacement is given as P(B1 and B2) = 335. This means that, out of all the possible combinations of beads in the bag, 335 of them contain two black beads. The probability of drawing one black bead is given as P(B1) = 310. This means that, out of all the possible combinations of beads in the bag, 310 of them contain one black bead. To calculate the probability of drawing a second black bead, given that the first bead is black, we can use the formula P(B2|B1) = P(B1 and B2) / P(B1). The probability of drawing one black bead is P(B1) = 310. The probability of drawing two black beads is P(B1 and B2) = 335. Therefore, P(B2|B1) = 335 / 310 = 1/3 = 0.33. This means that the probability of drawing a second black bead, given that the first bead is black, is 1/3 or 0.33.

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