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a 240 g bird flying along at 6.0 m/s sees a 12 g insect heading straight toward it with a speed of 30 m/s. the bird opens its mouth wide and enjoys a nice lunch. what is the bird's speed immediately after swallowing the insect?



Answer :

4.28 m/s is the bird's speed immediately after swallowing the insect.

A) The birds speed after swallowing the insect is = 4.84 m/s

Given data :

mass of bird ( M₁ )  = 240 g

speed of bird ( U₁ ) = 6 m/s

mass of insect ( M₂ ) = 12 g

speed of insect ( U₂ )  = 30 m/s

Determine the birds speed of the bird

A) Birds speed after swallowing the insect

we will apply the principle of momentum conservation

M₁U₁  +  M₂U₂ = ( M₁ +M₂ )V

= 240*6 - 12*30 = ( 240 + 12 ) V

= 1440 - 360 = 252 V

therefore ; V =  1080 / 252 = 4.28 m/s is the bird's speed.

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