an urn contains different colored marbles. the probability of drawing two green marbles from the urn without replacement is 320, and the probability of drawing one green marble is 25. what is the probability of drawing a second green marble, given that the first marble is green?

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19-12-2022
Mathematics

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an urn contains different colored marbles. the probability of drawing two green marbles from the urn without replacement is 320, and the probability of drawing one green marble is 25. what is the probability of drawing a second green marble, given that the first marble is green?

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kumarravichandra kumarravichandra · Answer 1 · 2022-12-24T08:01:00-05:00

The probability of drawing a second green marble, given that the first marble is green, is 0.8 or 80%.

The probability of drawing two green marbles from the urn without replacement is 320. This means that out of the total number of possible outcomes, 320 of them involve two green marbles.The probability of drawing one green marble is 25. This means that out of the total number of possible outcomes, 25 of them involve one green marble.Since the probability of drawing two green marbles is 320, and the probability of drawing one green marble is 25, the probability of drawing a second green marble, given that the first marble is green, is the ratio of the two probabilities. This ratio is 320/25, or 0.8, or 80%.

P(2 green marbles) = 320

P(1 green marble) = 25

P(second green marble | first marble is green) = P(2 green marbles) / P(1 green marble)

= 320 / 25

= 0.8 or 80%

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