if a 0.75 kg egg was moving at 12 m/s when it hits the ground, what is its change in momentum? if a 0.75 kg egg was moving at 12 m/s when it hits the ground, what is its change in momentum? -16 kgm/s 9 kgm/s -9 kgm/s 16 kgm/s

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19-12-2022
Physics

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if a 0.75 kg egg was moving at 12 m/s when it hits the ground, what is its change in momentum? if a 0.75 kg egg was moving at 12 m/s when it hits the ground, what is its change in momentum? -16 kgm/s 9 kgm/s -9 kgm/s 16 kgm/s

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fawadmohd fawadmohd · Answer 1 · 2022-12-24T13:07:18-05:00

momentum change = 24N Each ball's initial speed was 6 m/s. Each ball's initial momentum before to the collision was equal to 0.05 x 6 = 0.3 kg m/s. The balls' motion direction changes after the collision.

F average =m(vf v i)/tv, where f =0m/s and vi=12m/s.

F average =m(vf vi)/t=0.5(012)/0.25=24N as a result momentum.

The first step is to convert km/h to m/s, which gives us the result of 27 / 3.6 = 7.5 m/s. Given that we are aware of the deformation distance, which is 75 cm (0.75 meters), we then apply the first equation.

The energy an object has as a result of its motion is known as kinetic energy. According to classical mechanics, an object's kinetic energy (KE) is equal to half of its mass (1/2*m) times its velocity.

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