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an airplane flying into a headwind travels the 1800-mile flying distance between two cities in 3 hours. on the return flight, the airplane travels this distance in 2 hours and 30 minutes. find the airspeed of the plane and the speed of the wind, assuming that both remain constant.



Answer :

As a result, the wind is moving at 50 50 50 miles per hour, while the plane is traveling at 550 550 550 miles per hour distance.

3 hours and 18 minutes is equal to 3.3 hours. The speed of the aircraft in the direction of travel is 1650 divided by 3.3, which equals 500 miles per hour.

if p is the plane's speed and w is the wind speed, then p + w equals 550 and p - w equals 500.

2p = 1050\sp = 525

2w = 50\sw = 25

The plane is traveling at 525 miles per hour while the wind is blowing at 25 miles per hour. According to the distance-rate-time formula, if an object moves over a distance,

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