Answer :
The angular velocity of a tornado is 1.35 revolutions per second.
The angular velocity of a tornado is given by the formula omega = v/r, where v is the linear velocity of the wind and r is the radius of the tornado. Therefore it would be 1.35 revolutions per second.
The radius of the tornado is half of its diameter or 66.0 m/2 = 33.0 m. The linear velocity of the wind is given in km/h, so we need to convert it to m/s by dividing by 3.6. This gives us a linear velocity of 160 km/h/3.6 = 44.4 m/s. Substituting these values into the formula gives us an angular velocity of omega
= 44.4 m/s/33.0 m
= 1.35 revolutions per second.
Learn more about Angular Velocity here:
https://brainly.com/question/20432894
#SPJ4