Answer :
The probability of "heads" on the (6th) flip of this coin will be 2.
Given that,
Flipped a fair coin 5 times and got heads every time.
On the 6th flip is,
The chances of an event occurring are defined by probability. Probability has several uses in games, in business to create probability-based forecasts,
"Heads" is the result of the latest flip and the preceding four flips. The total sample space for the heads.
P(A^B)=(1/2)^5
The preceding four flips in a row all resulted in "heads."
P(B)=(1/2)^6
The probability that the 5th flip lands head is;
⇒ P(A^B)/p(B) = [tex]\frac{(\frac{1}{2}) ^{5} }{(\frac{1}{2}) ^{6} }[/tex]
⇒ P(A^B)/p(B) = [tex]\frac{1}{\frac{1}{2} }[/tex]
⇒ P(A^B)/p(B) = 2
Therefore,
The probability of "heads" on the (6th) flip of this coin will be 2.
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