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you invite your friend for the party. you have asked him to come at 9:00 pm. assuming that he has the same chance to arrive somewhere between 13 minutes before and 12 minutes after your defined time, what is the probability that he arrived before 9:02? a. 0.5769 b. 0.56 c. 0.6 d. 0.5384



Answer :

varshamittal029

The probability that our friend arrives at the party before 9:02 pm is 0.6, that is, option C.

Here, we are given that we invite our friend to a party and ask him to come at 9:00 pm.

Let X be the number of minutes past 9:00 after which he arrives.

Given that he has the same chance of arriving between 13 minutes before and 12 minutes after our defined time, ⇒ X ~ (-13, 12)

Now since X is uniformly distributed, P(a < X < d) is given as-

(d-c)/ (b-a)

Thus, the probability that he arrives before 9:02 will be-

P(X < 2) = {2-(-13)}/ {12-(-13)}

= (2 + 15)/ (12 + 13)

= 15/ 25

= 0.6

Thus, the probability that our friend arrives at the party before 9:02 pm is 0.6, that is, option C.

Learn more about the uniform distribution here-

https://brainly.com/question/22209943

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