Picklehead4194 Picklehead4194

19-12-2022
Mathematics

Answered

Maya said farewell to her favorite uncle as he boarded a plane for Paris. That night she dreamed about an airplane that ran into a thunderstorm and crashed into a mountain, killing everyone onboard. When she woke up, she learned that her uncle’s plane had encountered violent turbulence on the way to Paris and that several passengers had been injured on the flight. She concluded that this series of events (E) is very strong evidence that she has the ability to see distant things using only her mind (H).
Maya thinks that E is strong evidence for H. Assuming she has updated properly given her probability assignments, what does this mean about her assignments to P( E | ~H ) and P( E | H )? For each of these values, how might you challenge her assignment? (Don’t focus on P( H ) and P( ~H ).)

Answer :

smecloudbird18 smecloudbird18

24-12-2022

The likelihood of this question will be determined as P( E | ~H)=1 - P(E|H).

For independent events the probability P( E | H ) is calculated as:

P( E | H ) = P( E ) * P( E and H)

P( E and H) = P(E) * P(H).

Since the event E has already happened and is obvious, if P(E | H)>P(E | H) then the event E is dependent on the mind of maya, but if P(E | H)>P(E | H) then the event E is not dependent on the mind of maya.

In our situation, P(E | H), which means that the plane crushing is independent of Maya's thoughts, is the probability that will suit this argument.

Since it is illogical to claim that Maya can perceive far-off objects with her mind, the likelihood of this question will be determined as P( E | ~H ) = 1 - P( E | H ).

For independent events the probability P( E | H ) is calculated as

P( E | H ) = P( E ) * P( E and H)

P( E and H) = P(E) * P(H).

To learn more about independent events link is here

brainly.com/question/22881926

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