Suppose the drug atenolol is taken in 25 mg doses once a day to lower blood pressure. At the end of a 24 hour period, approximately 7 % of the atenolol is still present. (a) Find expressions for the quantities Q1, Q2, Q3, . . ., and Qn, representing the amounts of atenolol in the body right after taking the 1st, 2nd, 3rd doses respectively. Then write the expression for Qn in closed-form. Q1 = Q2 = Q3 = Qn = (b) Find expressions for the quantities P2, P3, P4, . . ., and Pn representing the amount of atenolol in the body right before taking the 2nd, 3rd, 4th doses respectively. Then write the expression for Pn in closed-form. P2 = P3 = P4 = Pn =

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19-12-2022
Mathematics

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Suppose the drug atenolol is taken in 25 mg doses once a day to lower blood pressure. At the end of a 24 hour period, approximately 7 % of the atenolol is still present. (a) Find expressions for the quantities Q1, Q2, Q3, . . ., and Qn, representing the amounts of atenolol in the body right after taking the 1st, 2nd, 3rd doses respectively. Then write the expression for Qn in closed-form. Q1 = Q2 = Q3 = Qn = (b) Find expressions for the quantities P2, P3, P4, . . ., and Pn representing the amount of atenolol in the body right before taking the 2nd, 3rd, 4th doses respectively. Then write the expression for Pn in closed-form. P2 = P3 = P4 = Pn =

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varshamittal029 varshamittal029 · Answer 1 · 2022-12-24T06:18:08-05:00

The values of the quantities Q1, Q2, Q3,... and Qₙ are

25, 25+25(0.07), 25+25(0.07)+25(0.07)² and Qₙ = 25(1-(0.07)ⁿ/(1-0.07)

Given:

Suppose the drug atenolol is taken in 25 mg doses once a day to lower blood pressure.

At the end of a 24 hour period, approximately 7 % of the atenolol is still present.

we are asked to find the expressions for the quantities Q1, Q2, Q3, . . ., and Qn, representing the amounts of atenolol in the body right after taking the 1st, 2nd, 3rd doses respectively.

hence:

Q1 = 25

Q2 = 25+25(0.07)

Q3 = 25+25(0.07)+25(0.07)²

Qₙ = 25(1-(0.07)ⁿ)/(1-0.07)

(b) we are asked to find expressions for the quantities P2, P3, P4, . . ., and Pn representing the amount of atenolol in the body right before taking the 2nd, 3rd, 4th doses respectively.

P2 = 25(0.07)

P3 = 25(0.07)+25(0.07)²

P4 = 25(0.07) + 25(0.07)² + 25(0.07)³

Pₙ = 25(0.07) × [1-(0.07)ⁿ]/[1-0.07]

Hence we get the required expressions.

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