Answered

what is the beat frequency heard when two organ pipes, each open at both ends, are sounded together if one pipe is 44 cm long and the other is 66 cm long? (the speed of sound is 340 m/s)



Answer :

If two open-ended organ pipes, one 44 cm long and the other 66 cm long, are sounded together, the beat frequency is 128.79 Hz.

Given length of first pipe (l1) = 44cm

length of second pipe (l2) = 66cm

Speed of sound (v) = 340m/s

let beat frequency =f

We know that f = c/∧

wavelength (∧) = 2l where l is length of pipe

frequency of first pipe (f1) = v/∧1 = v/2xl1 = 340/2x44x10-2 = 386.36Hz

frequency of second pipe (f2) = v/∧2 = v/2xl2 = 340/2x66x10-2=257.57Hz

Therefore the beat frequency f = f1 - f2

f = 386.36 - 257.57 = 128.79Hz

Hence the beat frequency is 128.79Hz

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