If two open-ended organ pipes, one 44 cm long and the other 66 cm long, are sounded together, the beat frequency is 128.79 Hz.
Given length of first pipe (l1) = 44cm
length of second pipe (l2) = 66cm
Speed of sound (v) = 340m/s
let beat frequency =f
We know that f = c/∧
wavelength (∧) = 2l where l is length of pipe
frequency of first pipe (f1) = v/∧1 = v/2xl1 = 340/2x44x10-2 = 386.36Hz
frequency of second pipe (f2) = v/∧2 = v/2xl2 = 340/2x66x10-2=257.57Hz
Therefore the beat frequency f = f1 - f2
f = 386.36 - 257.57 = 128.79Hz
Hence the beat frequency is 128.79Hz
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