Answer :
152.8 kg.m/s is the momentum of the combined masses. 15.28 m/s is the velocity of the combined masses.
To find the momentum of the combined masses after the collision, we can use the principle of conservation of momentum. This states that the total momentum of a closed system is conserved, meaning that the total momentum before the collision is equal to the total momentum after the collision. In this case, the total momentum before the collision is the momentum of the 4.00 kg ball plus the momentum of the 6.0 kg ball. The total momentum after the collision is the momentum of the combined masses.
We can express the principle of conservation of momentum as an equation: p_before = p_after
(m1 * v1) + (m2 * v2) = (m1 + m2) * vafter
where p stands for momentum, m for mass, and v for speed. The subscripts 1 and 2 refer to the two balls, and the subscript "before" refers to the momentum before the collision and "after" refers to the momentum after the collision.
Substituting in the known values, we get:
(4.00 kg * 11.2 kg.m/s) + (6.0 kg * 18 kg.m/s) = (4.00 kg + 6.0 kg) * v_after
44.8 kg.m/s + 108 kg.m/s = 10.00 kg * v_after
152.8 kg.m/s = 10.00 kg * v_after
v_after = 15.28 m/s
So the momentum of the combined masses after the collision is 152.8 kg.m/s and the velocity of the combined masses is 15.28 m/s.
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