A military jet cruising at an altitude of 12.0km and speed of 2100./kmh burns fuel at the rate of 78.7/Lmin. How would you calculate the amount of fuel the jet consumes on a 700.km mission?
Set the math up. But don't do any of it. Just leave your answer as a math expression.
Also, be sure your answer includes all the correct unit symbols.



Answer :

The amount of fuel the jet would consume on a 700 km mission is calculated to be fuel burning rate × 20 L

As we have to determine the amount of fuel the jet consumes on a 700 km mission and the speed of the jet is given to 2100 km/h, we first determine the time taken to complete the mission as follows;

T = altitude / speed

T =  (700 km / 2100 km/h)

T = 0.333 hours

As 1 hour = 60 minutes, therefore;

T = 0.333 hours × 60 = 20 minutes

Therefore the fuel consumed can be given by the following expression;

Fuel required for mission = fuel burning rate × 20

The rate of fuel burning is given to be 78.7/L.min

For one minute the fuel needed = 78.7 L

For 20 mins fuel needed = 78.7 × 20 L

Fuel required for mission = 78.7 × 20 L = 1574L

To learn more about speed; click here:

https://brainly.com/question/13943409

#SPJ4