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Find the x-intercept(s) and the coordinates of the vertex for the parabola y=-x-8x-16. If there is more than one x-intercept, separate them with commas.
x-intercept(s):
vertex

Find the xintercepts and the coordinates of the vertex for the parabola yx8x16 If there is more than one xintercept separate them with commas xintercepts vertex class=


Answer :

mhanifa

Answer:

  • x-intercept(s): (- 4, 0)
  • Vertex: (- 4, 0)

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Given parabola:

  • y = - x² - 8x - 16

Convert the equation into vertex form y = a(x - h)² + k, where (h, k) is the vertex.

  • y = - x² - 8x - 16
  • y = - (x² + 8x + 16)
  • y = - (x + 4)²

The vertex is ( - 4, 0).

The x-intercepts are the points with the y = 0, which as we see is same as the vertex:

  • - (x + 4)² = 0
  • x + 4 = 0
  • x = - 4

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