Answered

The diagram shows triangle FGH, with FG = 14cm, GH = 12cm and FH=6cm
i) Calculate the size of angle HFG



Answer :

sqdancefan

Answer:

  58.4°

Step-by-step explanation:

You have ∆FGH with f = 12 cm, g = 6 cm, and h = 14 cm, and you want to know the measure of angle F.

Law of cosines

The law of cosines tells you ...

  f² = g² +h² -2gh·cos(F)

Solving for angle F gives ...

  F = arccos((g² +h² -f²)/(2gh))

  F = arccos(88/168) ≈ 58.412°

Angle HFG is about 58.4°.

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