Answer :
The proportion of men would show positive on the test is 28.
In the given question, an investigator develops a new diagnostic test for prostate cancer. the sensitivity of this test is 80% and the specificity is 75%.
Suppose that the prevalence of prostate cancer who seek testing is 10%.
We have to find proportion of men would show positive on the test.
p (cancer)=10/100
p (cancer)=0.10
p (true positive)=80/100
p (true positive)=0.80
p (false positive)=1-75/100
p (false positive)=0.25
p (positive)=[0.10*0.80+0.80*0.25]*100
p (positive)=28
Hence, the proportion of men would show positive on the test is 28.
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