K, the spring constant, is 34 N/m.
Given that F = 34 N, the force applied to a spring
From its equilibrium position, where x = 0.73 m, a very light ideal spring moves by 0.73 m.
We must ascertain the spring's force constant or spring constant. In order to compute it, use Hooke's law. According to him, f = -kx k=f/x k=34/0.73 k=46.5 or k=46 gives the force acting on the spring when it compresses or stretches.
As a result, the spring's spring constant is 46 N/m.
The proportional constant k is used to represent the spring constant, which is a measure of a spring's stiffness. When a spring is squeezed or extended to the point that its length changes by a value x.
To know more about spring constant visit:-
https://brainly.com/question/14670501
#SPJ4