a 2 lane highway with a grade of 6% has a posted speed limit of 50 mph and a design speed of 55mph. the minor road approach grade is -1.5%. find the left turn departure sight distances for a passenger car taking a left turn from the minor road to the major road. answer should be in feet.

Question

16-12-2022
Mathematics

Answered

a 2 lane highway with a grade of 6% has a posted speed limit of 50 mph and a design speed of 55mph. the minor road approach grade is -1.5%. find the left turn departure sight distances for a passenger car taking a left turn from the minor road to the major road. answer should be in feet.

Answer :

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Yogeshkumari Yogeshkumari · Answer 1 · 2022-12-24T02:38:15-05:00

The left turn departure sight distances for a passenger car taking a left turn from the minor road to the major road is 121.275

Here we given that a 2 lane highway with a grade of 6% has a posted speed limit of 50 mph and a design speed of 55mph. the minor road approach grade is -1.5%.

And we need to find the left turn departure sight distances for a passenger car taking a left turn from the minor road to the major road.

While we looking into the given question we have identified that the following are the values given in the problem,

=> Speed limit = 50 mph

=> design speed = 55mph

=> grade = -1.5%

As per the length of the sight triangle leg or ISD along the major road is

determined using the following equation:

=> ISD = 1.47 V t

=> ISD = 0.278 V t

Where:

ISD refers length of sight triangle leg along major road, ft (m)

V refers design speed of major road, mph (km/h)

t refers time gap for minor road to enter the major road, sec

When we apply the value, then we get,

=> ISD = 1.47 x 55 x -1.5

=> ISD = -121.275

To know more about equation here.

https://brainly.com/question/10413253

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