Answer :
The z-score for 11 minutes of advertising time is approximately -0.667
Here we have given that a radio station claims that the amount of advertising each hour has a mean of 12 minutes and a standard deviation of 1.5 minutes. you listen to the radio station for 1 hour and observe that the amount of advertising time is 5 minutes.
And we need to calculate the z-score for this amount of advertising time.
While we looking into the given question, we have identified that Z-scores measure the distance of any data point from the mean in units of standard deviations and are useful because they allow us to compare the relative positions of data values in different samples.
Here the z-score for any single data value can be found by the formula:
z = (data value- mean) / standard deviation
Here from the information given we know:
Data value = 11 minutes
Mean = 12 minutes
Standard deviation = 1.5 minutes
When we apply the values on the formula then we get,
=> z = (11 - 12) / 1.5 = -0.667
To know more about z - score here.
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