a company that hires new graduates, requires that students sit for a special standardized test and score on the top 10% of the test to be admitted into the final stage of hiring. the mean of the score of the test is 800 and the population standard deviation is known to be 200. what is the minimum score an applicant needs to qualify for the final stage?



Answer :

The minimum score an applicant needs to qualify for the final stage 1056

In this question we have been given that students sit for a special standardized test and score on the top 10% of the test to be admitted into the final stage of hiring. the mean of the score of the test is 800 and the population standard deviation is known to be 200.

We need to find the minimum score an applicant needs to qualify for the final stage.

Z score is given by:

z = (raw score - mean) / standard deviation

here: mean = 800

and a standard deviation = 200

P(z > c) = 10% = 0.1

1 - P(z < c) = 0.1

P(z < c) = 0.9

P(z < c) = 1.282

So, substituting these values in above formula,

1.282 = (x - 800)/200

x - 800 = 256.4

x = 1056.4

x ≈ 1056

Therefore, the lowest possible score to qualify in the top 10% is approximately 1056

Learn more about the z score here:

brainly.com/question/25638875

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