Answer :
The minimum score an applicant needs to qualify for the final stage 1056
In this question we have been given that students sit for a special standardized test and score on the top 10% of the test to be admitted into the final stage of hiring. the mean of the score of the test is 800 and the population standard deviation is known to be 200.
We need to find the minimum score an applicant needs to qualify for the final stage.
Z score is given by:
z = (raw score - mean) / standard deviation
here: mean = 800
and a standard deviation = 200
P(z > c) = 10% = 0.1
1 - P(z < c) = 0.1
P(z < c) = 0.9
P(z < c) = 1.282
So, substituting these values in above formula,
1.282 = (x - 800)/200
x - 800 = 256.4
x = 1056.4
x ≈ 1056
Therefore, the lowest possible score to qualify in the top 10% is approximately 1056
Learn more about the z score here:
brainly.com/question/25638875
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