a flask containing neon gas is connected to an open-ended mercury manometer. the open end is exposed to the atmosphere, where the barometric pressure is 736. torr. the mercury level in the open arm is 4.7 cm above that in the arm connected to the flask of neon. what is the neon pressure, in torr? provide your answer in decimal notation rounded to the appropriate number of significant figures.

Question

16-12-2022
Chemistry

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a flask containing neon gas is connected to an open-ended mercury manometer. the open end is exposed to the atmosphere, where the barometric pressure is 736. torr. the mercury level in the open arm is 4.7 cm above that in the arm connected to the flask of neon. what is the neon pressure, in torr? provide your answer in decimal notation rounded to the appropriate number of significant figures.

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kumargaurav1012000 kumargaurav1012000 · Answer 1 · 2022-12-26T18:35:53-05:00

The pressure of the neon gas in torr is 780.98 torr. Let P = pressure of neon gas, P₀ = atmospheric pressure = 734 torr and h = height of mercury level in open arm = 4.7 cm

It follows that the neon pressure is higher than the atmospheric pressure since the height of the mercury in the open arm of the open-ended mercury mamometer is higher than that in the neon arm.

So, P = P₀ + ρgh where

P and P₀ are as given above

ρ = 13600 kg/m³,

g = 9.8 m/s²

h = 4.7 cm = 0.047 m

So, substituting the values

P = 734 torr + 13600 kg/m³ × 9.8 m/s² × 0.047 m

P = 734 torr + 6264.16 Pa

P = 734 torr + 6264.16 Pa × 0.0075 torr/1 Pa

P = 780.9812 torr

P ≅ 780.98 torr

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