Answer :
the separation that should be in a 5.6kg particle and a 3.1kg particle for their gravitational attraction to have a magnitude of 1.8 x10-12 n is 23m
Gravitational force:
The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.
Formula:
F= [tex]\frac{Gm1m2}{r^2}[/tex]
Where,
F is the gravitational force between two bodies
m1 is the mass of the first body
m2 is the mass of the second body
r is the distance between the centers of two bodies
Here,
m1=5.6kg
m2=3.1kg
F= 1.8 x10-12N
F=[tex]\frac{G*5.6*3.1}{r^2}[/tex]
⇒ 1.8 x10-12 =1.15×[tex]10^{-9}[/tex]/[tex]r^{2}[/tex]
⇒[tex]r^{2}[/tex] = 6.3×[tex]10^{2}[/tex]
⇒r = 2.3×10
⇒r = 23m
Therefore the separation should be 23m to have a magnitude of 1.8 x10-12
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